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AleksandrR [38]
3 years ago
10

A right pyramid has a square base with area 288 square cm. Its peak is 15 cm from each of the other vertices. What is the volume

of the pyramid, in cubic centimeters
Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0

The volume of the right pyramid is 864 cm³.

The given parameters;

  • Base area of the right pyramid, b = 288 cm²
  • Slant height of the pyramid, L = 15 cm

<h3>What is volume of right pyramid?</h3>

The volume of a right pyramid is one-third the product of the base and the perpendicular height.

The diagonal length of the right pyramid is calculated as follows;

d^2 = b^2 + b^2\\\\&#10;d^2 = (\sqrt{288})^2 + (\sqrt{288} )^2 \\\\&#10;d ^2 = 576\\\\&#10;d = \sqrt{576} \\\\&#10;d = 24 \ cm

The perpendicular height of the right pyramid is calculated as follows;

(\frac{d}{2} )^2 + h^2 = 15^2\\\\&#10;(\frac{24}{2})^2 + h^2 = 15^2\\\\&#10; 144 + h^2 = 225\\\\&#10;h^2 = 225-144\\\\&#10;h^2 = 81\\\\&#10;h = \sqrt{81} \\\\&#10;h = 9 \ cm

The volume of the right pyramid is calculated as follows;

V = \frac{1}{3} \times b \times h\\\\&#10;V = \frac{1}{3} \times 288 \times 9\\\\&#10;V = 864 \ cm^3

Learn more about volume of the right pyramid here: brainly.com/question/1273042

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X<br> 8<br> 17<br> Find the exact value of x.<br> X=
Furkat [3]

Answer:

621

629

Step-by-step explanation:

We know that

sin

(

x

+

y

)

=

sin

x

cos

y

+

sin

y

cos

x

If

cos

x

=

8

17

and

sin

y

=

12

37

We can use,

cos

2

x

+

sin

2

x

=

1

and

cos

2

y

+

sin

2

y

=

1

To calculate

sin

x

and

cos

y

sin

2

x

=

1

−

cos

2

x

=

1

−

(

8

17

)

2

=

225

17

2

sin

x

=

15

17

cos

2

y

=

1

−

sin

2

y

=

1

−

(

12

37

)

2

=

1225

37

2

cos

y

=

35

37

so,

sin

(

x

+

y

)

=

15

17

⋅

35

37

+

12

37

⋅

8

17

=

621

629

Answer link

Shwetank Mauria

Nov 22, 2016

sin

(

x

+

y

)

=

621

629

or

−

429

629

depending on the quadrant in which sine and cosine lie.

Explanation:

Before we commence further, it may be mentioned that as

cos

x

=

8

17

,

x

is in

Q

1

or

Q

4

i.e.

sin

x

could be positive or negative and as

sin

y

=

12

37

,

y

is in

Q

1

or

Q

2

i.e.

cos

y

could be positive or negative.

Hence four combinations for

(

x

+

y

)

are there and for

sin

(

x

+

y

)

=

sin

x

cos

y

+

cos

x

sin

y

, there are four possibilities.

Now as

cos

x

=

8

17

,

sin

x

=

√

1

−

(

8

17

)

2

=

√

1

−

64

289

=

√

225

289

=

±

15

17

and

as

sin

y

=

12

37

,

cos

y

=

√

1

−

(

12

37

)

2

=

√

1

−

144

1369

=

√

1225

1369

=

±

35

37

Hence,

(1) when

x

and

y

are in

Q

1

sin

(

x

+

y

)

=

15

17

×

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(2) when

x

is in

Q

1

and

y

is in

Q

2

sin

(

x

+

y

)

=

15

17

×

−

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

(3) when

x

is in

Q

4

and

y

is in

Q

2

sin

(

x

+

y

)

=

−

15

17

×

−

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(4) when

x

is in

Q

4

and

y

is in

Q

1

sin

(

x

+

y

)

=

−

15

17

×

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

Hence,

sin

(

x

+

y

)

=

621

629

or

−

429

629

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