Answer:
B and C
Step-by-step explanation:
Vertical angles are formed when you make lines make an x shape (or a turned x shape). The vertical angles are, on a normally positioned x the top and bottom angle, as well as the left and right angle. so every x has 2 vertcial angles unless the x is further split up.
So the part with angles 1. 2. 3 and 4 the top angle is 2, the bottom is 3, the left angle is 1 and the right angle is 4. This means the vertical angle pairs are 1 and 4 as well as 2 and 3.
So in total there are 2 x shapes, so 4 pairs of vertical angles. Here are all the vertical angles.
1 and 4
2 and 3
5 and 8
6 and 7
So from your choices you have 2 and 3 as choice B and 5 and 8 as choice C.
I believe the answer is 4 because 6m/29= 20.6897 and so then you do 20.6897 x 3= 62.0691. So 3 is too small so do 20.6897x 4= <span>82.7588. 82 >78 so the answer is that you need 4 boards.
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9514 1404 393
Answer:
see below
Step-by-step explanation:
The area of a square is the square of the side length, as shown in the given table.
The area of a circle is pi (π) times the square of the radius. For a radius that is the same as the side length of a square, the circle will have an area π times as large.
For an input of 3, the square area function outputs 9.
For an input of 3, the circle area function outputs 9π, about 28.3.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
2 boys 4 girls Add those together then divid And Then Use diffences And theres ur Awnser
