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choli [55]
3 years ago
9

Multiply: (3x)(x4 + 5)

Mathematics
2 answers:
Paul [167]3 years ago
7 0

Answer:

(3x) (X 4+5)

3x×(x×4+5)

3x×(4x+5)

12x^2+15x answer

Lelu [443]3 years ago
3 0

Answer:

12x² + 15x

Step-by-step explanation:

(3x × 4x) + ( 3x × 15)

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the average temperature at the south pole is -49.62and the average temperature at north pole is -34.68. how much higher is the a
Alecsey [184]
-34.68 - (-49.62) = -34.68 + 49.62 = 14.94 degrees warmer at the north pole
7 0
3 years ago
for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation
Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample proportion of defective items = 12,898

             s = sample standard deviation = 7,719

            n = sample size = 5

             \mu = population mean

<em> Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation. </em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ; </u>

P(-2.776 < t_4 < 2.776) = 0.95  {As the critical value of t at 4 degrees of

                                               freedom are -2.776 & 2.776 with P = 2.5%}  

P(-2.776 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.776) = 0.95

P( -2.776 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.776 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.776 \times {\frac{s}{\sqrt{n} } } , \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ]

                                = [ 12,898-2.776 \times {\frac{7,719}{\sqrt{5} } } , 12,898+2.776 \times {\frac{7,719}{\sqrt{5} } } ]

                               = [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

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