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Cerrena [4.2K]
2 years ago
13

Which points are located in the third quadrant?

Mathematics
1 answer:
8090 [49]2 years ago
8 0

Answer: for example (-2,-2), (-3,-6), and (-8,-10)

Step-by-step explanation: every point in the third quadrant is both negative.

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(10100)2-(111)2<br>binary subtraction <br>plz show process ​
statuscvo [17]

Step-by-step explanation:

  • (10100)2-(111)2
  • (1101)2

stay safe healthy and happy.

7 0
3 years ago
What value(s) of x will make each equation below true
Dahasolnce [82]

We need to solve for x. Let's try problem b:

2x-6=3x+1-x-7

Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:

2x-6=2x-6

Since this is true, your answer would be:

All real numbers

------------------------------------------------------------------

Let's solve for problem c:

3x+1=43

Let's isolate x, so subtract 1 from both sides:

3x=42

Since x can't have a coefficient, divide both sides by 3:

\frac{3x}{3}=\frac{42}{3}

x=14

So, only the value of 14 would make this equation true.

------------------------------------------------------------------

Let's try problem d:

4x-1=4x+7

Let's get our whole numbers on the right side. Add 1 to both sides:

4x=4x+8

Subtract 4x from the right side on both sides:

0=8

Since this is not true, your answer would be:

No solution

7 0
4 years ago
What is the sum of 3+(−4) = -1
Dmitry [639]
3+-4=-1
3-4=-1
-1=-1

so the answer is:
-1 = -1
8 0
3 years ago
Read 2 more answers
Help brainliest if all’ answers are correct if not report answer all’ questions plz<br> (10 points)
Naya [18.7K]
2. 11 2/16 that’s for answers number 2
3 0
3 years ago
Twenty different books are to be put on five book shelves, each of which holds at least twenty books.
olya-2409 [2.1K]

Answer:

(a) 10,626 different arrangements

(b) 95,367,431,640,625 different arrangements

(c) 2.5852017 × 10²² different arrangements

Step-by-step explanation:

(a) How many different arrangements are there if you only care about the number of books on the shelves (and not which book is where)?

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626 arrangements

(b) How many different arrangements are there if you care about which books are where, but the order of the books on the shelves doesn't matter?

Since the order of the books on the shelves does not matter,

The calculation is given as

5²⁰ = 95,367,431,640,625 arrangements

(c) How many different arrangements are there if the order on the shelves does matter?

Since order matters now

Step 1

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626

Step 2

We find the factorial of the number books

= 20!

= 2,432,902,008,176,640,000

Step 3

The different arrangements there are if the order on the shelves does matter is calculated

= 10,626 × 2,432,902,008,176,640,000

= 2.5852017 × 10²² different arrangements

8 0
3 years ago
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