I believe it’s 7y^4 but I may be wrong
x^2+7x-30=0 Rewrite the expression.
x^2+10x-3x-30=0 Factor the expressions.
x(x+10)-3 (x+10)=0 Factor the expression.
(x+10)(x-3)=0 Separate into possible cases.
x+10=0
Solve.
x-3=0
x1= -10
x2= 3
Answer:
a=10
b=37
Step-by-step explanation:
a+5 is equal to the opposite line, 15. 10+5=15 therefore, a must equate to 10
3b is the same angle as 111 therefore 3*b has to equate to 111. 111 divided by 3 equals 37. B has to then equate to 37 to make the proper angle.
Hope my explanation wasn't too confusing, and hope this helps! Good luck!!!
The first answer is -15-20x.
The second answer is -42b-21.
Ask in the comments section if you want me to explain, other than combining like terms and using the distributive property. I hope this helps!
Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, is 37°. We can see from the diagram that would be 143°.
Also, the new bearing is N 25°E. So, would be 25°.
Now we can find . As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.