All categories

2 years ago

Order the fractions from smallest to largest

Mathematics

1 answer:

vampirchik [111]2 years ago

8 0

Answer:

1. 1/2 6/10 2/3 4/5

2. 3/10 1/3 1/2 3/5

3. 1/10 1/5 1/3 2/4

Step-by-step explanation:

Hope this helps! :)

You might be interested in

Ok I need help um thanks :)

strojnjashka [21]

Answer:

40% male and 60% female

Step-by-step explanation:

Add all the experiments, and then divide the variables by the number of experiments

Variables :T and H

8 0

3 years ago

Read 2 more answers

What is the measure of <5 <5=

CaHeK987 [17]

Answer:

700

Step-by-step explanation:

5 0

3 years ago

If f(x)= 5x, what is f^-1(x)?

Helen [10]

Step-by-step explanation:

$f( x) {}^{ - 1} \\ f(x) = 5x \\ y = 5x \\ x = 5y \\ y = \frac{x}{5} \\ f(x) {}^{ - 1} = \frac{x}{5}$

8 0

2 years ago

(a) 34 is 85% of what number?

Tju [1.3M]

Answer:

$40$

hope this helps you.

Can I have the brainliest please?

6 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago