Question

(-r-5)-(-2r-4) help me solve pls lol

Answer 1

answer:

$r - 1$

Step by step explanation:

Step 1: Distribute

$( - r - 5) - ( - 2r - 4) \\ ( - r - 5) + 2r + 4$

Step 2: Eliminate redundant parenthesis

$( - r - 5) + 2r + 4 \\ - r - 5 + 2r + 4$

Step 3: Add numbers

$- 3 \purple{ - 5} + 2r + \purple{4} \\ - r \purple{ - 1} + 2r$

Step 4:Combine like terms

$\purple{ - r } - 1 + \purple{2r} \\ \purple{1r} - 1$

Step 5:Multiply by 1

$1r - 1 \\ r - 1$

Hopefully it's help

Answer 2

I copy MissJoy2 answer cuz her/his answer is right