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2 years ago

Use the fraction model to multiply: three multiplied by three fifths. Leave your answer as an improper fraction.

Mathematics

1 answer:

Katena32 [7]2 years ago

8 0

Answer:

it is six fifths your welcome

Step-by-step explanation:

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Let A = −2 2 1 −3 1 1 2 0 −1 and B = 2 −1 0 1 2 1 −1 −2 4 . Use the matrix-column representation of the product to write each co

BigorU [14]

Answer:

AB = $\left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]$

Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = $\left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]$

B= $\left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]$

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * $\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]$ + 1 $\left[\begin{array}{ccc}2\\1\\0\end{array}\right]$ + (-1) $\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]$

AB Column 2 = (-1) $\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]$ + 2 $\left[\begin{array}{ccc}2\\1\\0\end{array}\right]$ + (-2) $\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]$ = $\left[\begin{array}{ccc}4\\3\\0\end{array}\right]$

AB Column 3 = (0) $\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]$ + (1) $\left[\begin{array}{ccc}2\\1\\0\end{array}\right]$ + 4 $\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]$ = $\left[\begin{array}{ccc}6\\5\\-4\end{array}\right]$

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = $\left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]$

4 0

4 years ago

Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0

4 years ago

What is the product?(4y − 3)(2y2 + 3y − 5)8y3 + 3y + 158y3 − 23y + 158y3 − 6y2 − 17y + 158y3 + 6y2 − 29y + 15

motikmotik

We need to find the product of :

$\mleft(4y-3\mright)\mleft(2y2+3y-5\mright)$

So, the result as following:

$\begin{gathered} \mleft(4y-3\mright)\mleft(2y^2+3y-5\mright) \\ =4y\cdot(2y^2+3y-5)-3\cdot(2y^2+3y-5) \\ =8y^3+12y^2-20y-(6y^2+9y-15) \\ =8y^3+12y^2-20y-6y^2-9y+15 \\ \\ =8y^3+6y^2-29y+15 \end{gathered}$

So, the answer is the option 4. 8y3 + 6y2 − 29y + 15

5 0

1 year ago

For the following system, if you isolated x in the first equation to use the Substitution Method, what expression would you subs

tatiyna

$-x-2y=-4 \\ 3x+y=12 \\ \\ \hbox{the first equation:} \\ -x-2y=-4 \ \ \ \ \ \ |+2y \\ -x=2y-4 \ \ \ \ \ \ \ \ |\times (-1) \\ x=-2y+4$

The expression you would substitute for x is -2y+4. The answer is d.

4 0

4 years ago

Ху 4 32 5 40 756 972 ОА. В ОВ. 4 Ос. 32 OD. 8

dsp73

Answer:

Step-by-step explanation:

mark me as brainliest ppls :)

5 0

3 years ago