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omeli [17]
3 years ago
7

A rational number is a number that can be written as a _____ of two integers

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0
The correct answer is: Ratio
 
Explanation:
<span>A rational number is a number that can be written as a ratio of two integers.
 
A rational number can be represented in the mathematical form as follows:
 
</span>\frac{a}{b}<span> (where a and b are integers)
 
For Example: </span>\frac{8}{7}<span>, </span>\frac{11}{97} etc.<span> are the rational numbers.
 
Information: Ratio can also be represented as a:b (with colon).</span>
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Answer:

(1) equilateral

(2)isosceles

(3)scalene

(4)right

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2 years ago
In the expression 3x² + y − 5, which of the following choices is the exponent in the term 3x²?
quester [9]

Answer: the exponent would be the 2

Step-by-step explanation:

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3 years ago
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A spool contains 270 inches of wire. How many pieces of wire, each with the a length of 1 7/8 inches, can be cut from the spool?
prisoha [69]
You would be able to cut 144 pieces of wire from the spool because 270/1 7/8 (or 1.875) equals 144
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2 years ago
11) Solve the multiplication equation. Check your answer.<br> 39 = 13y what does y equal?
denis-greek [22]

Answer:

y = 3

Step-by-step explanation:

39 = 13y

y = 3 (explanation: by dividing 13)

Check answer:

39 = 13(3)

39 = 39

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2 years ago
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Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
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