-2(5y - 5) - 3y < = -7y + 22
-10y + 10 - 3y < = -7y + 22
-13y + 10 < = -7y + 22
-13y + 7y < = 22 - 10
-6y < = 12
y > = -12/6
y > = -2....answer B
Answer:
the probability that the shipment is accepted is 0.8865
Step-by-step explanation:
Given the data in the question;
N = 86, n/d = 5 and n = 2
now, without replacement
the probability that the shipment is accepted will be;
probability that the shipment is accepted = probability that non is defectives
so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))
p( non is defective ) = ( 81 / 86) × (80/85)
p( non is defective ) = 0.8865
Therefore, the probability that the shipment is accepted is 0.8865
Pie r squared is the area of a circle, so 9^2(3.14etc) = so 255 square yards. So 255 x 15 = $3,825
the standard form of a quadratic is simply the equation with all variables and constant on the left-hand-side.
y = 3x² <--- general form
-3x² + y = 0 <--- standard form.
H(k) = k^2 - k so we just substitute in 10 for K.
h(10) = 10^2 - 10. 100 - 10 = 90
h(10) = 90.
