Question

Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid's weight, Pythagoras's weight would still be 1/4 pound less than he did in January. What is Euclid's weight? (a) Write an equation that represents the scenario. Begin by defining your variable (b) Solve the equation. Show your work. (c) What is Euclid's weight? (d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined 1 pounds. What is Riemann's weight, and what is Pythagoras's weight? weight of the three dogs is Show your work.​

Answer 1

The weight of Euclid is 10.625 pounds, and the weight of Riemann is 21.25 pounds.

• Let the current weight of Euclid = x
• Let the current weight of Pythagoras = T
• Let the January weight of Pythagoras = y

The expression that represents the given scenario is written as;

• when Pythagoras lost 13 pounds: T =  y - 13
• when Pythagoras gains 1.2 times Euclid's weight: = T + 1.2x

when Pythagoras weight is 1/4 pound less than weight in January:

T + 1.2x + 0.25 = y

y- 13 + 1.2x + 0.25 = y

1.2x - 12.75 = 0

Euclid's weight is calculated as follows;

1.2x = 12.75

$x = \frac{12.75}{1.2} \\\\x = 10.625 \ pounds$

The weight of Riemann is calculated as follows;

$= 2 (10.625)\\\\= 21.25 \ pounds$

Learn more about word problem to algebra here: brainly.com/question/21405634