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Nastasia [14]
2 years ago
12

SImplify: (2m)^5 Please help if possible :)

Mathematics
2 answers:
lukranit [14]2 years ago
6 0
Your answer should be 32m^5
(2m)(2m)
4m^2(2m)
8m^3(2m)
16m^4(2m)
32^5
Bad White [126]2 years ago
6 0

2m x 2m
4m^2 x 2m
8m^3 x 2m
16m^4 x 2m
32^5
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Please help!!!!!!!!!!!!!!!
tamaranim1 [39]

Answer:

(y¹-y¹/x¹-x¹)

8-11/10-19

-3/-9

1/3

Step-by-step explanation:

1/3 or one-third is your answer!

7 0
2 years ago
What is 3x + 10(1-7X)
Alinara [238K]

Answer:

-67x + 10

Step-by-step explanation:

3x + 10(1 - 7x)

(use distributive property)

3x + 10 - 70x

(simplify)

3x - 70x + 10

-67x + 10

5 0
3 years ago
Read 2 more answers
If the distance between two objects is increased, the gravitational attraction between them will: increase decrease remain the s
natulia [17]
It decreases
The further two objects are, the gravitational attraction decreases and the closer two objects are, the gravitational attraction increases
8 0
3 years ago
Read 2 more answers
Given f: ℝ → ℝ and : ℝ → ℝ , for the following, find f(g(x)) and g(f(x)), and state the domain.
horrorfan [7]

Answer:

Remember, (f\circ g)(x)=f(g(x)) and the range of g must be in the domain of f.

a)

f(g(x))=f(x-1)=(x-1)^2-(x-1)=x^2-2x+1-x+1=x^2-3x+2

g(f(x))=g(x^2-x)=(x^2-x)-1=x^2-x-1

The domain of f(g(x)) and g(f(x)) is the set of reals.

b)

f(g(x))=f(\sqrt{x}-2)=(\sqrt{x}-2)^2-x=\sqrt{x}^2-2*2*\sqrt{x}+2^2-x=-4\sqrt{x}+4

g(f(x))=g(x^2-x)=\sqrt{x^2-x}-2

The domain of f(g(x)) is the set of nonnegative reals and the domain of g(f(x)) is the set of number such that x^2-x\geq 0

c)

f(g(x))=f(\frac{1}{x-1})=(\frac{1}{x-1})^2=\frac{1}{(x-1)^2}

g(f(x))=g(x^2)=\frac{1}{x^2-1}

The domain of f(g(x)) is the set of reals except the 1 and the domain of g(f(x)) is the set of reals except the 1 and -1

d)

f(g(x))=f(\frac{1}{x-1})=\frac{1}{(\frac{1}{x-1}-1)}=\frac{1}{\frac{2-x}{x-1}}=\frac{x-1}{2-x}

g(f(x))=g(\frac{1}{x+2})=\frac{1}{(\frac{1}{x+2}-1)}=\frac{1}{\frac{-x-1}{x+2}}=\frac{x+2}{-x-1}

The domain of f(g(x)) is the set of reals except 2, and the domain of g(f(x)) is the set of reals except -1.

e)

f(g(x))=f(log(2(x+3)))=f(log(2x+6))=log(2x+6)-1

g(f(x))=g(x-1)=log(2(x-1)+6)=log(2x+4)

The domain of f(g(x)) is the set of nonnegative reals except -3. The domain of g(f(x)) is the set of nonnegative reals except -2.

3 0
3 years ago
Write an inequality that represents the given graph
Ugo [173]

Answer:

I believe the answer is C.

Step-by-step explanation:

:)

Hope this helps!

<3

3 0
2 years ago
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