Answer:
Easy-to-use virtual robotics and STEM platform tailored to serve every student at every level!
CoderZ is a powerful, award-winning online platform.
Explanation:
CoderZ is a powerful, award-winning online platform through which students learn valuable STEM skills such as coding, robotics, and physical computing. CoderZ is highly flexible and designed for use in the classroom or through a wide range of remote learning environments. Computers and technology are everywhere. Studying science, technology, engineering and math gives kids valuable skills for the future and develop life-skills like computational thinking, critical thinking and problem-solving as well.
STEM and CS education focuses on how to approach complex problems, break down the challenges into small pieces and approach resolving them in a logical manner – critical skills for any career path.
Answer:
The Anonymous Block will be:
1 DECLARE
2
3 lv_grade_row grade%rowtype;
4 lv_gr_avg grade.gr_t1%type;
5 lv_std_name varchar2(80);
6 cursor cursor_grade is select * from grade;
7
8 BEGIN
9
10 select avg(gr_t1) INTO lv_gr_avg from grade;
11 open cursor_grade;
12 fetch cursor_grade INTO lv_grade_row;
13
14 while cursor_grade%found loop
15
16 if
17 lv_grade_row.gr_t1>lv_gr_avg then lv_std_name :=
lv_grade_row.std_fname|| ' ' ||lv_grade_row.std_lname|| ' ' ||
lv_grade_row.gr_t1;
18 dbms_output.put_line(lv_std_name);
19
20 end if;
21 fetch cursor_grade into lv_grade_row;
22
Explanation:
Answer:
The character which is not found on a standard keyboard is called __symbol_____ Charater
Explanation:
Answer:
hello your question is incomplete attached below is missing part of the question
Determine how many bits are needed for the opcode
answer : 7 bits
Explanation:
Given data:
memory unit = 26 bits per word
Instruction set consists = 756 different operations
Determine how many bits are needed for the opcode
First we determine The number of bits required to represent 756 operations
= = 9.56 ≈ 10 bits
finally the number of bits needed for the opcode can be determined by
and
since 2^10 > 756 hence the number of bits will be 10 bits
Answer:
D. 25x24x23x22x21.....3x2x1.
Explanation:
The ceasar cipher is a encryption technique, that uses a combination of information or keys to encrypt an information.
The 25 shift ceasar cipher has 25 different combinations, so the number of probable random cipher substitution is 25!,
That is = 25 × 24×23× 22×..... ×2×1.