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Alborosie
2 years ago
9

What is the range of possible sizes for side x?

Mathematics
1 answer:
posledela2 years ago
4 0

Answer:

x = 3.96

Step-by-step explanation:

apply the pitagoras theorem

x =

\sqrt{ {2.8}^{2}  +  {2.8 }^{2} }

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Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

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Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

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Everywhere you see x,y,z, you replace with their value.

1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21

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<u>B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21

B also doesn't equal 21. On to the next one...

<u>C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2</u>

Everywhere you see x,y,z you replace with their value.

1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21

Both sides of the equation equal 21 which means C is our answer.

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