i) the least positive coterminal angle can be found by subtracting 2pi from your original angle. We subtract 2pi because 11pi/3 is larger than 2pi.
So: 11pi/3 - 2pi = 11pi/3 - 6pi/3 = 5pi/3 or 
ii) The reference angle is the smallest angle you can make with the x-axis. Since 5pi/3 is in Quadrant IV, the reference angle is found by:
2pi - 5pi/3 = 6pi/3 - 5pi/3 = pi/3 or 
iii) 5pi/3 or 300 degrees is found in Quadrant IV.
Step-by-step explanation:
what huh?????? i dont understand
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is
Multiply both sides by r :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for :
Then as gets arbitrarily large, the term will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer:
9(8+1)
Step-by-step explanation:
9(8+1) = 9×9 = 81
72+9 = 81
Answer:
y-2=2/3(x+1) OR y=2/3x+8/3
Step-by-step explanation:
y=2/3x-2 (2/3 represents your slope)
plug into this equation y-y1=m(x-x1) (m represents your slope, y1 and x1 are you points)
so y-2=2/3(x+1) OR y=2/3x+8/3 (move the -2 over, distribute the 2/3 to (x+1) and then add 2/3 to the 2 you moved over)
