2 years ago

How do I solve this?

Mathematics

1 answer:

Tju [1.3M]2 years ago

7 0

Answer: A: 3x^2y^(3/2)

Step-by-step explanation:

This can be written as

(81*x^8*y^6)^(1/4)

Then multiply each exponent by (1/4):

81^(1/4)*x^(8(1/4))y^6(1/4))

81^(1/4) = 3

x^(8(1/4)) = x^2

y^6(1/4)) = y^(3/2)

The result: 3x^2y^(3/2)

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Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts

nignag [31]

Answer:

$30 + 0.05x < 60$

The number of texts she can have is less than 600.

Step-by-step explanation:

Total monthly charge

30 + 0.05 for each text.

So, for x tests, the charge is:

$C(x) = 30 + 0.05x$

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

$C(x) < 60$

$30 + 0.05x < 60$

The solution is:

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