1. Domain.
We have
in the denominator, so:
![x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\ (x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}](https://tex.z-dn.net/?f=x%5E2-2x-3%5Cneq0%5C%5C%5C%5C%28x%5E2-2x%2B1%29-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-2%5E2%5Cneq0%5Cqquad%5Cqquad%5B%5Ctext%7Buse%20%7Da%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D%5C%5C%5C%5C%28x-1-2%29%28x-1%2B2%29%5Cneq0%5C%5C%5C%5C%0A%28x-3%29%28x%2B1%29%5Cneq0%5C%5C%5C%5C%5Cboxed%7Bx%5Cneq3%5Cqquad%5Cwedge%5Cqquad%20x%5Cneq-1%7D)
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
Answer:
Evening walk is shorter.
Step-by-step explanation:
We have been given that a nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. We are asked to find the shorter walk.
Let us compare both fractions by making the same denominator.
Upon making common denominator, we can see that two-thirds are equal to four sixths.
Since three-sixths is less than four-sixths, therefore, evening walk is shorter.
We will draw two rectangles, one with 6 sub-parts and other with three sub-parts.
We will shade 2 parts out of 3 sub-parts to represent 2/3 and shade 3 parts out of 6 sub-parts to represent 3/6.
Then we will further divide three sub-parts into 6 sub-parts as shown in the diagram that will represent 4/6.
Answer:
A
Step-by-step explanation:
The answer is 523 because 4,707 divide 9 to be equal numbers for each one I hope it helps
