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Ludmilka [50]
3 years ago
7

Help me!!! Is for today!!! And what is its congruency?

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

Side-Side-Side (SSS) Congruence Property

Step-by-step explanation:

Congruence just means that two things are of the same size. For instance, if you have two congruent side lengths, they are the same length. In this picture, you can see that both triangles have a side with one dash and a side with two dashes. In geometry, to show that two lines are congruent you give them the same number of dashes, and therefore you know for sure that those two pairs of sides are congruent. Finally, the triangles share a side length, so you know that that side length is equal for them. Therefore, the appropriate congruence property here is SSS, since you know that three pairs of sides are congruent.

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lions [1.4K]

there is no mode

no number repeats

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What is the solution set to the inequality 2²-x≥6
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
X+y=5<br> x^y+y^x=17<br> solve for the value of y and x
pentagon [3]
X = 2 
<span>y = 3 </span>

<span>2 + 3 = 5 </span>
<span>2³ + 3² = 17 </span>

<span>------------------- </span>

<span>BUT: </span>

<span>x + y = 5 </span>
<span>x^y + y^ x = 17 </span>

<span>y = 5 - x</span>
7 0
3 years ago
Solve for x.<br> 3x - 3<br> 4x - 6<br> X =<br> = [?]
Lina20 [59]
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7 0
2 years ago
Read 2 more answers
F:[1/2,infinity)—&gt;[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain
dexar [7]

Answer:

f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

\pm \sqrt{y-3/4}=x-1/2

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

\sqrt{y-3/4}=x-1/2

Add 1/2 on both sides:

1/2+\sqrt{y-3/4}=x

The last step is to switch x and y:

1/2+\sqrt{x-3/4}=y

y=1/2+\sqrt{x-3/4}

f^{-1}(x)=1/2+\sqrt{x-3/4}

8 0
3 years ago
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