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2 years ago

I'll give you brainliest for the correct answer!!!

Mathematics

2 answers:

BaLLatris [955]2 years ago

8 0

Answer:

x = -5.39

Step-by-step explanation:

x + (−2.4) = −7.79

x = −7.79 + 2.4

x = -5.39

Lunna [17]2 years ago

8 0

Answer:

-5.39

Step-by-step explanation:

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-14(3a+6)=12(6-4a)+12 and steps please

Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

14(3a+6)+12(6-4a)+12=0 (using distributive property)

42a+84+72-48a+12=0 ( adding the like terms )

-6a+168=0

-6a=-168

6a=168

$a=\frac{168}{6}$

Therefore a=28

Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

8 0

2 years ago

1/3 of the fish in the tank are snappers. 2/9 of the fish are catfish and the rest are goldfish. There are 40 goldfish in the ta

Paraphin [41]

Find fraction of snappers and catfish:

1/3 + 2/9 = 3/9 + 2/9 = 5/9

Find fraction of goldfish:

1 - 5/9 = 4/9

4/9 = 40 goldfish

1/9 = 40 ÷ 4 = 10

9/9 = 10 x 9 = 90

Answer: 90 fish in the tank

3 0

3 years ago

Read 2 more answers

Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t

schepotkina [342]

Answer:

(A) Set A is linearly independent and spans $R^3$ . Set is a basis for $R^3$ .

Step-by-Step Explanation

Definition (Linear Independence)

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

Definition (Span of a Set of Vectors)

The Span of a set of vectors is the set of all linear combinations of the vectors.

Definition (A Basis of a Subspace).

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors $A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right)$ , we are to decide which of the given statements is true:

In Matrix $A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right)$ , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. $R^3$ has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans $R^3$ .