This is a table with 6 lines.
In each line, the number in the first column is the 'x' value.
All you have to do on each line is ...
--- substitute the 'x' value in (100 + 23x), simplify it,
and write the result in the middle column
then
--- substitute the 'x' number in 90(1.2ˣ) , simplify it,
and write the result in the last column.
On the first line, x=0.
100 + 23x = 100 + 0 = 100. Write 100 in the middle column.
90(1.2ˣ) = 90(1) = 90. Write 90 in the last column.
Then go on to the second line, where x=1.
You'll make it.
You can check the following
C=4
C=5
C=11
500 people took the survey.
12 out of 15 people is 80% of the population. 12/15 = 0.80
Thus, 80% of the population prefers eating in the restaurant.
If 400 represents the people who prefers eating in the restaurant; then, 400 is the 80% of the population. To get the total population or 100%, we must divide 400 by 0.80 or 80%
400 / 0.80 = 500 people.
Out of the 500 people, 400 selected eating in the restaurant while the remaining 20% of the population or 100 people selected cooking at home.
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
