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Nostrana [21]
3 years ago
11

Find a polynomial which, when added to the polynomial 3x^2+3x-1 is equivalent to the following expressions:

Mathematics
1 answer:
goblinko [34]3 years ago
3 0
It should be -1x^2 -3x -2
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Find the slope of (-10,-4) and (5,5)
ValentinkaMS [17]

Answer:

15/9... i believe :)

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Given lines a and b are parallel, and m<1 = 50, Find m<4
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M1 = m4 = 50 (A) is the answer
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Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.
Katyanochek1 [597]

The first thing we are going to do for this case is define variables.

We have then:

x: number of days

y: number of pages remaining.

We write the linear equation that models the problem:

y = -25x + 400

The intersection with the vertical axis is:

We evaluate x = 0:

y = -25 (0) + 400\\y = 0 + 400\\y = 400

We get the point:

(x, y) = (0, 400)

The intersection with the horizontal axis is:

We evaluate y = 0:

0 = -25x + 400\\25x = 400

x = \frac{400}{25}\\x = 16

We get the point:

(x, y) = (16, 0)

Answer:

The graph is:

y = -25x + 400

Graph located in the bottom left.

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3 years ago
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Sabrina bought 8 gallons of paint. After she painted her shed, she had 4 gallons left over. How much paint did Sabrina use on he
gizmo_the_mogwai [7]
Pretty sure its 4 gallons 
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3 years ago
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The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension T T and inv
emmasim [6.3K]

Answer: T=40.96\ KgF

Step-by-step explanation:

We know that:

n: The number of vibrations per second of the nylon guitar string.

T: Tension.

L: The length of the string.

Since  n  varies directly with the square root of the  T and inversely with  L, the equation has the following form:

n=k*\frac{\sqrt{T} }{L}

Where "k" is the constant of variation.

Knowing that when n=15 and L=0.6, T=256, we can find the value of "k":

n=k*\frac{\sqrt{T} }{L}\\\\L*n=k\sqrt{T}\\\\\frac{L*n}{\sqrt{T}}=k\\\\k=\frac{(0.6)(15)}{\sqrt{256}}\\\\k=0.5625

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into n=k*\frac{\sqrt{T} }{L} and solve for T:

12=(0.5625)\frac{\sqrt{T} }{0.3}\\\\\frac{12(0.3)}{(0.5625)}=\sqrt{T}\\\\(6.4)^2=T\\\\T=40.96\ KgF

8 0
3 years ago
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