Find out what number goes into 8 and 10 then figure out how many times that number goes into 100
AM=3x+3
AB=8x-6
AB=2AM
AM=AB/2
AM=(8x-6)/2
AM=4x-3
3x+3=4x-3
4x-3x=3+3
x=6
AM=3x+3
AM=3(6)+3
AM=18+3
AM=21
Let x be the smallest number.
x+(x+1)+(x+2)=384
3x+3=384
3x=381
x=127
The three consecutive numbers are 127, 128 and 129.
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