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pickupchik [31]
3 years ago
12

One cell phone company offers a plan that costs $26.99 and includes unlimited night and weekend minutes. Another company offers

a plan that costs $18.99 and charges $0.35 per minute during nights and weekends. For what numbers of night and weekend minutes does the second company's plan cost more than the first company's plan? Starting at minutes, the second company's plan will cost more than the first company's plan.
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Given :

One cell phone company offers a plan that costs $26.99 and includes unlimited night and weekend minutes.

Another company offers a plan that costs $18.99 and charges $0.35 per minute during nights and weekends.

To Find :

For what numbers of night and weekend minutes does the second company's plan cost more than the first company's plan.

Solution :

Let, after n number of nights and weekends second plan is most costly.

So,

18.99+0.35x > 26.99\\\\0.35x > 8\\\\x>22.85

Therefore, after 22 night and weekends second plan is  most costly.

Hence, this is the required solution.

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3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)

From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . .  (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)

(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5

From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3

x = 3, y = 0.5, z = -3.5
8 0
4 years ago
House prices in the neighborhood average at $90.05 per square foot. If the house has 1055 square feet, what should be its price?
telo118 [61]

Answer:

C. $95,000

Step-by-step explanation:

90.05 times 1055 is $95,000.75 the closest number to that is $95,000.

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3 years ago
Jane gets paid $120 for 8 hours. How much does she get paid an hour?​
AleksAgata [21]

Answer:

$15 an hour

Step-by-step explanation:

To find this, we divide 120 by 8.

120 ÷ 8 = 15

So Jane gets $15 an hour

I hope this helped, please mark Brainliest, thank you!

8 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

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zaharov [31]

Answer:

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Step-by-step explanation:

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f(x) = log(2x+1) - 1

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