Simplify\:\frac{\sqrt{5}}{\sqrt{3}}

The grace period is the _____. maximum amount of money you can charge on the credit card time before the credit card company sta

GenaCL600 [577]

I'll just clarify the choices you gave:
-maximum amount of money you can charge on the credit card time before the credit card company starts charging late fees
-least amount of money that must be paid at the end of a month
-period of time before the credit card company starts charging interest

If these are correct, then the answer is 'period of time before the credit card company starts charging interest'.

5 0

3 years ago

Read 2 more answers

The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine. The temperature in Mia

Nastasia [14]

Answer:

$y=\frac{x-22}{3} ; y=20$

Step-by-step explanation:

Let Temperature of Maimi $T_{m}$ and that of Bangor be $T_{b}$

Given in the condition is $T_{m}$ is 22 more than 3 times $T_{b}$

i.e. $T_{m}$ = 22+ 3 * $T_{b}$

Hence

$T_{m} - 22 = 3 * T_{b}$

$T_{b} = \frac{T_{m}-22}{3}$

Here also we are given that $T_{m}$ =82

$T_{b} = \frac{82-22}{3}$

$T_{b} = \frac{60}{3}$

$T_{b} = 20$

8 0

2 years ago

Read 2 more answers

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

a

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

b

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

2 years ago

Janice is making a soup recipe that normally yields 8 servings. The recipe calls for 3 pounds of chicken and a certain number of

kondaur [170]

Answer:Janice needs 5 pounds of vegetables.

Step-by-step explanation:

5 0

2 years ago

A scale on a map shows that 1 inch = 25 miles. How many inches on the map represent 100 miles? *

Lilit [14]

Answer:

4 inches

Step-by-step explanation:

Every 25 miles the map shows 1 inch
100 miles is equal to 4 x 25 miles, thus 100 miles on the map will be 4 times longer than 1 inch => 4 inches

8 0

2 years ago