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3 years ago

29. Which property justifies the statement below?

Mathematics

1 answer:

OleMash [197]3 years ago

4 0

Answer:

d I think is right sorry If it's not

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1 Two high school basketball teams have identical records of 15 wins and 2 losses. Sunnyside High School's mean score is 50 poin

yanalaym [24]

Answer:

Lin likes Sunnyside High School

Step-by-step explanation:

The Mean Absolute Deviation (MAD) is a measure of how dispersed the values are, in this case the score of the teams. So, Sunnyside High School, with a low MAD, scores nearly the same amount of points in every game.

6 0

4 years ago

Evaluate the expression when a=2 and b=20

vagabundo [1.1K]

50(2) -2(20) +6 = ?
100 - 40 + 6 = ?
60 + 6 = ?
66

8 0

4 years ago

Read 2 more answers

Is the given number a solution of the equation?<br> 8=2+3; 10

kykrilka [37]

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation. So therefore, it is false based on the equation.

7 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

How do you find the domain of a function?

emmasim [6.3K]

Domain of the function is x in order pair for example (2,3) 2 is the domain

6 0

3 years ago