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Harman [31]
2 years ago
9

F(x) 5x/x-2

Mathematics
1 answer:
Phoenix [80]2 years ago
6 0

Answer:

Vertical asymptote: x=2

Horizontal asymptote: y=5

Step-by-step explanation:

Hi there!

The parent function for a rational function has a horizontal asymptote at y=0 and a vertical asymptote at x=0.

First, we want to perform long division on 5x/x-2. Please check the image attached.

The result is 5+\displaystyle\frac{10}{x-2}.

Here are the transformations of a rational function:

f(x)=\displaystyle\frac{a}{b(x-h)}+k

a = vertical stretch

b = horizontal stretch

h = horizontal translation

k = vertical translation

Stretches don't change the location of the asymptotes, only the translations do.

According to 5+\displaystyle\frac{10}{x-2}, we applied a horizontal translation of 2 units right and a vertical translation of 5 units up. Therefore, our asymptotes are now x=2 and y=5.

I hope this helps!

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Sophie [7]

1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

4 0
1 year ago
12p &lt; 96<br> A. p &lt; 8<br> B. p &lt; 108<br> C. p &lt; 84<br> D. p &gt; –8
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Solution:

<u>Note that:</u>

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<u />

3 0
3 years ago
Read 2 more answers
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Feel free to change it up a little.
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Now solve.
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number two:

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