Answer:
So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10
Step-by-step explanation:
(3, 1) and (0, 10)
m=y²-y¹/x²-x¹
m=10-1/0-3
m=9/-3
m=-3
y=mx+b
y-y=m(x-x1)
y-1=-3(x-3)
y-1=-3x+9
+1 +1
y=-3x+10
The average slope (s) on the interval [a, b] is given by
s = (f(b) -f(a))/(b -a)
When there are a lot of computations to do, it is convenient to let a machine do them. The intervals and slopes are ...
[0, 5] : 5
[-3, 3] : 0
[-5, 3] : -2
[-3, 5] : 2