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3 years ago

For f(x) = 4 - x and g(x) = 3x² + x + 5, find the following functions.

Mathematics

1 answer:

creativ13 [48]3 years ago

5 0

Look at the attached photo for the answers.

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Round 2.571 to 2 decimal place

aalyn [17]

The answer is 2.57.

7 0

4 years ago

Mr.Martin states that in order for the solution to the equation 3x + q = 6 to be positive, the value of q must be less than 6. S

Virty [35]

Answer:

Mr. Martin's statement is correct.

Step-by-step explanation:

First we select a value of q that is less than 6:

q = 3

Then we <u>write the equation:</u>

3x + 3 = 6

And <u>solve for x</u>:

3x = 6 - 4

3x = 3

x = 3/3

x = 1

The solution is positive because x > 0.

Then we select a value of q that is not less than 6:

q = 9

Then we <u>write the equation:</u>

3x + 9 = 6

And <u>solve for x</u>:

3x = 6 - 9

3x = -3

x = -3/3

x = -1

The solution is negative because x > 0.

5 0

3 years ago

The volume of a cube is 27 cubic in. Which expression represents s, the lenght of a side of the cube

Y_Kistochka [10]

Answer:

Hello i am here to give the answer of the above question................................................................................................................................

Solution:Here

Given,

Volume of a cube is 27 so.

Length of a side of the cube =?

So I think the correct answer of this question is 3

Thank you......... ..................

8 0

2 years ago

Which is the simplified form of the expression (6^-4)^-9/6^6

natima [27]

Given expression: $\frac{((6^{-4})^{-9})}{6^6}$ .

First we would apply exponents of exponent rule on the top.

$(a^m)^n= a^{m\times n}$

Therefore,

$((6^{-4})^{-9}) = (6)^{-4\times -9} = (6)^{36}$

= $\frac{((6^{-4})^{-9})}{6^6} = \frac{6^36}{6^6}$

Applying quotient rule of exponents.

$\frac{a^m}{a^n} = a^{m-n}$

$Therefore \ \frac{6^{36}}{6^6} =6^{36-6}$

= $6^{30}$

<h3>Therefore, $6^{30}$ is the simplified form of the expression $\frac{((6^{-4})^{-9})}{6^6}.$ </h3>

5 0

3 years ago

Read 2 more answers

What is the range of the function: h(x)=x+1/x^2 - 7x+10

Elina [12.6K]

Answer:

(-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

Step-by-step explanation:

To make it easier to differentiate, we'll rewrite the function as ...

h(x) = 2/(x-5) -1/(x-2)

Then the derivative is ...

h'(x) = -2/(x-5)^2 +1/(x-2)^2

This will be zero when ...

-2(x-2)^2 +(x-5)^2 = 0

-2(x^2 -4x +4) +(x^2 -10x +25) = 0

-x^2 -2x +17 = 0

x^2 +2x +1 = 17 +1

x +1 = ±√18 = ±3√2

x = -1 ±3√2

The values of the function at these locations are ...

h(-1-3√2) = -1 +(2/3)√2 ≈ -1.9428

h(-1+3√2) = -1 -(2/3)√2 ≈ -0.0572

Then the range of h(x) is ...

(-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

5 0

3 years ago