Help please I don’t understand
1 answer:
You might be interested in
For this case we have that the generic equation of the line is given by:
Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:
On the other hand we have:
Substituting values we have:
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:
On the other hand we have:
Substituting values we have:
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
The graph of linear equation 2x - 3y = -12 is as shown below.
I this question, we have been given a linear equation 2x - 3y = -12
We need to graph the points.
For x = 1,
2(1) - 3y = -12
2 - 3y = -12
-3y = -14
y = 14/3
For x = 0,
2(0) - 3y = -12
y = (-12)/(-3)
y = 4
For x = -1,
2(-1) - 3y = -12
-3y = -12 + 2
y = (-10) / (-3)
y = 10/3
So, we get coordinates (1, 14/3), (0, 4) and (-1, 10/3)
Now we plot these points.
The graph of linear equation 2x - 3y = -12 is as shown below.
Learn more about the linear equation here:
#SPJ1
