A triangle has two sides of length 9 and 3. What is the smallest possible whole-number length
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The volume of a room = length * width * height
=12z³-27z
And by the analysis:
The volume = 12z³-27z
= ( 3z ) ( 4z²-9 ) ⇒ by taking (3z) common
= ( 3z )( 2z+3 )( 2z-3 ) ⇒ <span>the difference between two squares
So </span><span>the dimensions of the room will be 3z , 2z+3 , 2z-3
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I have attached tha problem
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=12z³-27z
And by the analysis:
The volume = 12z³-27z
= ( 3z ) ( 4z²-9 ) ⇒ by taking (3z) common
= ( 3z )( 2z+3 )( 2z-3 ) ⇒ <span>the difference between two squares
So </span><span>the dimensions of the room will be 3z , 2z+3 , 2z-3
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I have attached tha problem
</span>