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vekshin1
3 years ago
8

What is the value of x?

Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

5 sqrt(3) =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan 30 = x/15

15 tan 30 = x

15 ( sqrt(3)/3) = x

5 sqrt(3) =x

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73

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4 0
3 years ago
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Factor the following polynomial 2x^2+9x+9
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Calculate the mean deviation for the numbers: 75, 83, 96, 100, 121 and 125 A 14.33 B 15 C 15.33 D 16
sveta [45]

Answer:

c) 15.33

Step-by-step explanation:

lets find the mean first

mean = sum of the data values / number of data (n)

= 75 + 83 + 96 + 100 + 121 + 125 / 6

= 600/6

= 100

Next, let 'x' represent each data value and 'a' represent the the mean

now, calculate the deviation from each data point

75 - 100 = - 25

83 - 100 = -17

96 - 100 = - 4

100 - 100 = 0

121 - 100 = 21

125 - 100 = 25

Then, find the absolute value of each deviation and sum them up

that is | a - x |

| -25 | + | -17 | + | -4 | + | 0 | + | 21 | + | 25 |

= 25 + 17 + 4 + 0 + 21 + 25

= 92

now, calculate the mean of the absolute value

92/6 = 15.33

4 0
4 years ago
the height of a ball dropped from a 160 foot building after t seconds is represented by h(t)=160-16t^2.how high will the ball be
alekssr [168]

Answer:

The height of the ball after 3 secs of dropping is 16 feet.

Step-by-step explanation:

Given:

height from which the ball is  dropped = 160 foot

Time = t seconds

Function h(t)=160-16t^2.

To Find:

High will the ball be after 3 seconds = ?

Solution:

Here the time ‘t’ is already given to us as 3 secs.

We also have the relationship between the height and time given to us in the question.

So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:

h(3)=160-16(3)^2

h(3)=160-16 \times 9

h(3)=160-144

h(3)=16

Therefore, the height of the ball after 3 secs of dropping is 16 feet.

8 0
3 years ago
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