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Bogdan [553]
3 years ago
6

When Cameron moved into a new house, he planted two trees in his backyard. At the

Mathematics
1 answer:
blagie [28]3 years ago
5 0
O
Mmm
Momo IMO mo

P momm I’m
Ml
Lmk


Momm
You might be interested in
Solve the equation. Check for extraneous solutions.
Sliva [168]
Assume
if |a|=b
a=b and -a=b

so

9|9-8x|=2x+3
divide both sides by 9
|9-8x|=2/9x+1/3
assume
9-8x=2/9x+1/3 and
-9+8x=2/9x+1/3


9-8x=2/9x+1/3
times 9 both sides
81-72x=2x+3
add 72x both sides
81=74x+3
minus 3
78=74x
divide both sides by 74
39/37=x

other one
-9+8x=2/9x+1/3
multiply both sides by 9
-81+72x=2x+3
minus 2x both sides
-81+70x=3
add 81 to both sides
70x=84
divide boh sides by 70
x=6/5


x=39/37 and 6/5
check

9|9-8(39/37)|=2(39/37)+3
2646/37=189/37
false

9|9-8(6/5)|=2(6/5)+3
351/5=27/5
false

no soltion evidently, weird

3 0
3 years ago
its telling me to write (2m³)⁴ in expanded form and also how do i write (4n⁵) (4n⁵) (4n⁵) (4n⁵) (4n⁵)(4n⁵) exponential​
weeeeeb [17]
(2m^3)^4

Expanded Form:
16m^12

(4n⁵)(4n⁵)(4n⁵)(4n⁵)(4n⁵)(4n⁵)

24n^5
6 0
3 years ago
Consider the following hypothesis test: : : A sample of provided a sample mean of . The population standard deviation is . Enter
scoundrel [369]

The answer to this problem is  B.

7 0
3 years ago
Help pls homework!! Sorry if I’m wasting time.
forsale [732]

Answer:

Blanks top to bottom: 6^2, 36, 9, 108, 101

Step-by-step explanation:

Use PEMDAS which stands for parentheses, exponents, multiplication, division, addition, and subtraction. Listed in this specific order, you must look and solve for each one first, starting with parentheses.

4.

12 × ((4+2)^2/4) - 7

Solve for inside of parentheses first:

12 × ((6)^2/4) - 7

12 × (36/4) - 7

12 × 9 - 7

108 - 7

101

4 0
3 years ago
There are 80 runners to start a race. IN the first half of the race, 1/4 of them dropped out. In the second half of the race , 1
mihalych1998 [28]

Answer:

48

Step-by-step explanation:

80 divided by 4 is 20 so thats 1/4 of 80

80-20=60

1/5 of 60 = 12

20+12=32

80-32=48

5 0
3 years ago
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