Test the following point in the inequality

A line that passes through the points (−5, 7) (10, 1). Using the mx+b format

lianna [129]

Answer:

y=2x-19

Step-by-step explanation:

I'm guessing you mean slope intercept form y=mx+b

If so, first you would have to find the slope of the line

To do that, use the formula y2-y1/x2-x1

Remember you can pick any coordinate pair for this

I will pick 1=y2 -5=y1 10=x2 and 7=x1

When I put that in the equation I get 1-(-5)/10-7

Overall I get 6/3, or 2

Now to find the y intercept, you plug in the slope and one of the coordinates(any is fine)

I will pick (10,1)

1=y and 10=x and 2=m

1=2(10)+b

this simplifies to 1=20+b

now subtract 20 from both sides and get -19 = b

Now you have your equation y=2x-19

6 0

3 years ago

Read 2 more answers

Is 1.8 repeating rational or irrational number

Yuliya22 [10]

Answer:

Irrational number

Step-by-step explanation:

The number 1.8 isn't repeating so it wouldn't be a repeating rational number.

8 0

2 years ago

John’s friend told him that he could earn $49 for handing out flyers at a local concert John wants to calculate the hourly rate

son4ous [18]

$\frac{3.5x}{3.5} = \frac{49}{3.5}$
$x = 14$

5 0

3 years ago

Carol is solving the inequality 3 have?<br> There are infinitely many solutions.<br> There are only two solutions.<br> There is

schepotkina [342]

Answer:

There are infinitely many solutions

Step-by-step explanation:

Firstly, I need to change f to x as the system won’t accept the word f

Let’s take a look at the question;

3 is less than x

The domain of our answer lies in the the range of values where we have numbers that are greater than 3

This means we can rewrite our inequality as x is greater than 3

Now, simply because we have an infinite amount of numbers which are greater than 3 of which x can take any of the values, we can conclude that the number of values we have for x are infinite and does not end

This makes us have infinitely many solutions for the value of x

6 0

3 years ago

Kendall had $1000 in a savings account at the beginning of the semester. She has a goal to have at least $350 in the account by

USPshnik [31]

Answer:

11 weeks

Step-by-step explanation:

First we need to check what variables we have.

Beginning Balance = $1000

Goal = $350

Withdrawal = $55 per week

Now let's declare a variable as the number of weeks.

Let x = number of weeks

1000 - 55x = 350

-55x = 350-1000

-55x = -650

Then we divide both sides by -55 to find the value of x.

x = 11.81 or 11 since we're looking for how many weeks in total

Now let's see if we still have 350 if we have a total of 11 as the value of x.

1000 - 55(11) = 350

1000 - 605 = 350

395 = 350

We can see that Kendall will have $395 compared to the $350 goal.

So Kendall can withdraw $55 a week for 11 weeks to still be within her goal of having $350 in her savings account.

6 0

3 years ago