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Ostrovityanka [42]
3 years ago
5

Area of general quadrilateral is______

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

1/2*diagonals length *(sum of the height of two triagles

You might be interested in
Q14
posledela

Answer:

42.6cm

Step-by-step explanation:

The sum total of all the sides of the shape is the perimeter of the shape. Hence;

Perimeter = x+3 + 4 + x+9 + 2x+5

Perimeter = 4x + 21

Given

Area of the figure = 75cm^2

Area = (x+3)(2x+5) + (2x+1)(6)

75 = 2x²+5x+6x+15+12x+6

75 =  2x²+23x+21

2x²+23x+21-75 = 0

2x²+23x-54 = 0

x = -23±√23²-4(2)(-75)/4

x = -23±√529+600/4

x = -12±√1129/4

x = -12+33.6/4

x = 21.6/4

x = 5.4

Recall that;

Perimeter = 4x+21

Perimeter = 4(5.4) + 21

Perimeter = 21.6+21

Perimeter = 42.6cm

Hence the perimeter is 42.6cm

8 0
3 years ago
If p(x)=x2+2x-5 and qıx)=x-3, what is p(x) - g(x)?
Alenkinab [10]

Answer:

C. x2+x-2

Step-by-step explanation:

5 0
3 years ago
What is the slope of the line<br><br> A.1/2<br><br> B.1<br><br> C.-2<br><br> D.2
Eduardwww [97]
I think the answer is A
4 0
3 years ago
Read 2 more answers
So i am dealing with equations with triangles, complimentary and supplementary, so what is 42 square + x = 180, so what is the n
Genrish500 [490]
-1584.
multiply 42 times 42 the subtract that from 180
5 0
3 years ago
____________________
luda_lava [24]

Angle BOC = 120

PROOF

Angle A + Angle B + Angle C = 180

So, Angle B + Angle C = 120 (Angle A = 60)

Now 1/2 (Angle B + Angle C) = 60

1/2 Angle B + 1/2 Angle C = 60..............i

In triangle BOC

1/2 Angle B + 1/2 Angle C + Angle BOC =180

(BO and CO are angle bisectors)

Or 60 + Angle BOC = 180 (using i)

OR ANGLE BOC = 120

6 0
4 years ago
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