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castortr0y [4]
3 years ago
9

This is a khan question please help

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

The answer is D

Step-by-step explanation:

You divide each by 20

bezimeni [28]3 years ago
5 0

Answer:

D. 20(r+3t)

Step-by-step explanation:

I found the answer online.

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Solve the system of equations by substitution.<br> y = 3x-7<br> 2x + 5y = 16
Virty [35]

Answer:

In the picture

Step-by-step explanation:

Hope that helps.

8 0
3 years ago
What is the mixed number of 96/8
lions [1.4K]
The answer is 12 because i divide 96 / 6 

(sorry i dont have division sign)

3 0
3 years ago
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
3 years ago
1. A student took 60 minutes to answer a combination of 20 multiple-choice and extended-response questions. She took 2 minutes t
Darina [25.2K]

Answer:

1) m=15 and r =5

2) 4 and 2 ml

3) x= 0.5 and y = -1

Step-by-step explanation:

given that m multiple choice questions and r extended response questions.

Also given that a) m+r = total no of questions =20 ... i and

                        2m+6r = total time taken = 60  ... ii

b) Divide second equation by 2, m+3r = 30  ... iii

                                                  m+r  = 20   ... i

Subtract to get 2r =10 or r =5

m = 20-5 = 15

Verify: m+r = 15+5 =20

and     2m+6r = 30+30 = 60 minutes.  

Hence verified

--------------------------------------

2) Let a litres of 20% solution and b litres of 50% solution be mixed

a) Then total volume = 6 ml = a+b  ... i

Resulting solution = 30% of 6 ml = 1.8 = 0.2a+0.5b ... ii

b) Solve i and ii

b = 6-a: substitute in ii.

0.2a + 3-0.5a = 1.8

Or a = 4 ml and b = 2ml

Verify: Total volume = a+b =6ml and

concentration = 0.2(4)+0.5(2) = 1.8 = 30% of 6 ml.

Thus verified

---------------------------------

3) 2x-3y=4 ...i

  2x-5y =6... ii

Because x term has the same coefficient in both the equations, elimination is easier.

i-ii gives 2y =-2 or y =-1

Substitute in i, 2x+3 =4 or x = 0.5

So answer is x = 0.5 and y =1


6 0
3 years ago
Please help answer this if your able two :)) ♡
andreev551 [17]
Answer:

Y + 3= 3/4( x - 7)
8 0
3 years ago
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