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kirza4 [7]
3 years ago
12

Write an expression for “ the quotient of x and 4“

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0
The answer is: x ÷ 4 !! hope that helps
serious [3.7K]3 years ago
3 0

Answer:

x/4

Step-by-step explanation:

I hope this helped

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Write an equation for Greg ordered some books online for $6 each. He paid a total of $3 for shipping. The total cost of the purc
telo118 [61]

Answer: he bought 12 books.

Step-by-step explanation:

Let x represent the number of books that Greg bought.

Greg ordered some books online for $6 each. This means that x books would cost $6x

He paid a total of $3 for shipping. The total cost of the purchase was $75.00. This means that

6x + 3 = 75

Subtracting 3 from the left hand side and the right hand side of the equation, it becomes

6x + 3 - 3 = 75 - 3

6x = 72

Dividing the left hand side and the right hand side of the equation by 6, it becomes

6x/6 = 72/6

x = 12

6 0
4 years ago
Mr. Grocer has 421 dozen eggs valued at $0.59 per dozen. How much are the eggs worth altogether?
Karo-lina-s [1.5K]

Answer:

248.39

Step-by-step explanation:

421 × .59 =248.39

3 0
3 years ago
Read 2 more answers
Find the exact value of each trigonometric function sin 90
Vilka [71]
   sin 90 is simply 1, pretty straightforward
8 0
3 years ago
The Pew Research Center has conducted extensive research on the young adult population (Pew Research website, November 6, 2012).
Rudik [331]

Answer:

a) 0.93 - 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.908

0.93 + 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.952

The 95% confidence interval would be given by (0.908;0.0.952)

b) 0.21 - 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.163

0.21 + 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.257

The 99% confidence interval would be given by (0.163;0.0.257)

c) The margin of error for part a is:

ME= 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.0224

And for part b is:

ME=2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.0470

So then the margin of error is larger for part b.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.93 - 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.908

0.93 + 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.952

The 95% confidence interval would be given by (0.908;0.0.952)

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.21 - 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.163

0.21 + 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.257

The 99% confidence interval would be given by (0.163;0.0.257)

Part c

The margin of error for part a is:

ME= 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.0224

And for part b is:

ME=2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.0470

So then the margin of error is larger for part b.

7 0
3 years ago
How would you write the equation ????
Elden [556K]
If f(x)=e^x-1 +5 and g(x) is a transformation or, the same thing just moved, and its y-intercept is -3 then its equation would be:

D) g(x)=e^x-1 -3
8 0
3 years ago
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