Solve the inequality:12+x≥3(x-6)

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

8 0

Hello there! :)

The first step is to use the Distributive Property.

It states that

a(b+c)=ab+ac

Let's distribute 3, using this property:

3(x-6)=3x-18

Now, our inequality looks like so:

12+x≤3x-18

The next step is to move the variables to the left, using the opposite operation:

12+x-3x≤-18

12-2x≤-18

Now, move all the numbers to the right, using the opposite operation:

-2x≤-18-12

-2x≤-30

Divide both sides by -2 to isolate x.

Remember that when we divide by a negative variable, we change the inequality sign:

x≥15

Therefore, x≥15

Hope it helps.

~A lonely teen who helps others with a smile

-Grace :-)

Good luck.

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$\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {0.34} & {34\%} &{5-6}& {50} & {0.32} & {32\%} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {} & {} &{5-6}& {50} & {} & {} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}$