<u>Answer:</u>
<em>In a cross-site request forgery, browser </em><u><em>Link</em></u><em> help send a forged HTTP request.</em>
<u>Explanation</u>:
<em>CSRF is a kind of attack which compels the user to click on the unwanted links </em>or make him to perform some actions on the browser which the user is not intended to do so.
<em>They mainly target on Change request such as fund transfers, modifying their mail id’s etc</em>.
So they do all things by knowing Social engineering tricks and transfer the control of the <em>user to one another application created by the hackers and obtain the information and it is not just for theft of data.
</em>
Answer:
all the questions that she is submitting is all the questions im getting wrong please someone answer them for me please help me out
Explanation:
im not that smart and i need help please someone
Answer:
Replace /* Your solution goes here */ with the following lines of code
for(i = 0;i<SCORES_SIZE-1;i++)
{
bonusScores[i]+=bonusScores[i+1];
}
Explanation:
The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).
Using an iterative variable, i
It adds the current element (element at i) with the next element; element at i + 1.
The full code becomes
#include<iostream>
using namespace std;
int main(void) {
const int SCORES_SIZE = 4;
int bonusScores[SCORES_SIZE];
int i = 0;
bonusScores[0] = 10;
bonusScores[1] = 20;
bonusScores[2] = 30;
bonusScores[3] = 40;
for(i = 0;i<SCORES_SIZE-1;i++)
{
bonusScores[i]+=bonusScores[i+1];
}
/* Your solution goes here */
for (i = 0; i < SCORES_SIZE; ++i) {
printf("%d ", bonusScores[i]);
}
printf("\n");
return 0;
}
See attachment for .cpp file
Answer:
Having lunch with a friend
Explanation:
Answer: Type the name of the database and select where to locate it.
Explanation: