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2 years ago

Which of the following statements is not true about peer-to-peer (p2p) software?.

1 answer:

7 0

The statement which is not true about peer-to-peer (P2P) software is: P2P software includes any data storage device that you can remove from a computer and take with you to a peer’s computer.

<h3>What is a peer-to-peer (P2P) software?</h3>

A peer-to-peer (P2P) software can be defined as a software application that are used to directly exchange (share) files or communicate on computer systems that are connected to each other through a wired or wireless network and over the Internet.

<h3>Examples of peer-to-peer (P2P) software</h3>

Some examples of peer-to-peer (P2P) software on computer networking include the following:

Kazaa

Limewire

Morpheus

Acquisition

BearShare

In conclusion, a peer-to-peer (P2P) software provides its end users with direct access to another computer when performing these tasks:

File sharing
Internet meeting
Ch-at messaging

Read more on peer-to-peer (P2P) software here: brainly.com/question/26198872

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a student combined 45.3 ml of a 0.549 m calcium nitrate ca(no₃)₂ solution with 75.05 ml of a 1.321 m ca(no₃)₂ solution. calculat

Maksim231197 [3]

The concentration of the final solution of Ca(NO₃)₂ made by combining 45.3 mL of a 0.549 M Ca(NO₃)₂ solution with 75.05 mL of a 1.321 M Ca(NO₃)₂ solution is 1.03 M

We'll begin by calculating the number of mole of Ca(NO₃)₂ in each solution. This can be obtained as follow:

<h3>For solution 1:</h3>

Volume = 45.3 mL = 45.3 / 1000 = 0.0453 L

Molarity = 0.549 M

Mole = Molarity x Volume

Mole of Ca(NO₃)₂ = 0.549 × 0.0453

<h3>For solution 2:</h3>

Volume = 75.05 mL = 75.05 / 1000 = 0.07505 L

Molarity = 1.321 M

Mole = Molarity x Volume

Mole of Ca(NO₃)₂ = 1.321 × 0.07505

Next, we shall determine the total mole of Ca(NO₃)₂ in the final solution. This can be obtained as follow:

Mole of Ca(NO₃)₂ in solution 1 = 0.0249 mole

Mole of Ca(NO₃)₂ in solution 2 = 0.0991 mole

Total mole = 0.0249 + 0.0991

<h3>Total mole = 0.124 mole</h3>

Next, we shall determine the total volume of the final solution.

Volume of solution 1 = 0.0453 L

Volume of solution 2 = 0.07505 L

Total Volume = 0.0453 + 0.07505

<h3>Total Volume = 0.12035 L</h3>

Finally, we shall determine the concentration of the final solution. This can be obtained as follow:

Total Volume = 0.12035 L

Total mole = 0.124 mole

<h3>Concentration =?</h3>

Concentration = mole / Volume

Concentration = 0.124 / 0.12035

<h3>Concentration = 1.03 M</h3>

Therefore, the concentration of the final solution of Ca(NO₃)₂ is 1.03 M

Learn more: brainly.com/question/25469095

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3 years ago

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3 years ago

Match the following regulations to their appropriate categories.

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3 years ago

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The ratio of the amount of vitamin A in cow milk to the amount of vitamin A in goat milk is

miv72 [106K]

Answer:

2080 IU

Explanation:

Given

Ratio of vitamin A in cow milk to goat milk = 3 : 4

Required

Determine the content of vitamin A in goat milk if cow milk has 1560 IU

The given parameters shows a direct proportion.

Let G represents Goat and C represent Cow

Given that there exists a direct proportion;

C = K * G where K represents the constant of proportionality.

Solving for K when C = 3 and G = 4

C = K * G becomes

3 = K * 4

3 = 4K

Divide through by 4

¾ = K

K = ¾

Now, solving for G given that C = 1560IU;

We'll make use of the same formula as above

C = K * G

Substitute 1560 for C and ¾ for K; the expression becomes

1560 = ¾ * G

Multiply both sides by 4

4 * 1560 = 4 * ¾ * G

6240 = 3 * G

Multiply both sides by ⅓

⅓ * 6240 = ⅓ * 3 * G

2080 = G

G = 2080

Hence, the vitamin A in the goat milk is 2080IU

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4 years ago