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Furkat [3]
3 years ago
10

Evaluate the expression for f=2. 7+3f=

Mathematics
2 answers:
Anettt [7]3 years ago
6 0

Answer:

=

2

7

+

3

Step-by-step explanation:

nexus9112 [7]3 years ago
6 0

Answer:

13

Step-by-step explanation:

7+3f=

7+3(2)=

7+6=

13

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Find an expression which represents the difference when (9x−6) is subtracted from (6x+7) in simplest terms.
evablogger [386]

Answer:

3x + 1

Step-by-step explanation:

9x -6 -6x +7

9x-6x -6 +7

3x +1

8 0
3 years ago
(Multiple choice)
spayn [35]
I believe the answer is A
5 0
2 years ago
Help me plzz help me plzz​
Alik [6]

Answer:

44.1 mm^2

Step-by-step explanation:

The formula for a trapezoid is 1/2(b1 + b2)h

A= 1/2(12.5 + 8.5) 4.2

 = 1/2x21x4.2

 =44.1

4 0
2 years ago
How do you fine out if y is a linear function of x on a graph
mote1985 [20]

Answer: If a vertical line can be drawn to touch the graph of a function in more than one place, then is NOT a function of . If it is not possible to draw a vertical line to touch the graph of a function in more than one place, then y is a function of x.

6 0
3 years ago
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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