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elena-14-01-66 [18.8K]
3 years ago
12

Drag the point A to the location indicated in each scenario to complete each statement.

Mathematics
1 answer:
Art [367]3 years ago
4 0

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

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3 0
3 years ago
Read 2 more answers
Anu
bija089 [108]

Answer:

Circumference of Circle B=19.625cm

Step-by-step explanation:

The circumference formula is: 2pie(r) = pie(d)

We have diameter of the first circle which is 6. Now, because the diameter of second circle is 25% greater than this,

Hence, we add 25% in 6:

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Therefore, we have diameter of 6.25 for circle B.

Now, we need to find the circumference of the Circle A.

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Now use the proportional reasoning to find Circumference of Circle B:

circumference of Circle A/diameter Circle A = circumference of Circle B/diameter Circle B

18.84/6=circumference of Circle B/6.25

Cross multiply and divide:

(18.84times6.25)/6 = Circumference of Circle B

Solve:

Circumference of Circle B=19.625cm

Hope this helps!

Mark brainliest if you think i helped! Would really appreciate!

7 0
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What number goes on top and how do you solve it.
vekshin1
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4 0
3 years ago
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