Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6
Or uniform acceleration, a = - 1.6
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:
Answer:
The point (0, 0) in the graph of f(x) corresponds to the point (4, -7) in the graph of g(x)
Step-by-step explanation:
Notice that when we start with the function , and then transform it into the function:
what we have done is to translate the graph of the function horizontally 4 units to the right (via subtracting 4 from the variable x), and 7 units vertically down (via subtracting 7 to the full functional expression).
Therefore, the point (0, 0) in the first function, will now appeared translated 4 units to the right (from x = 0 to x = 4) and 7 units down (from y = 0 to y = -7).
then the point (0, 0) after the translation becomes: (4, -7)