Answer:
the third graph
Step-by-step explanation:
To determine the probability that exactly two of the five marbles are blue, we will use the rule of multiplication.
Let event A = the event that the first marble drawn is blue; and let B = the event that the second marble drawn is blue.
To start, it is given that there are 50 marbles, 20 of them are blue. Therefore, P(A) = 20/50
After the first selection, there are 49 marbles left, 19 of them are blue. Therefore, P(A|B) = 19/49
Based on the rule of multiplication:P(A ∩ B) = P(A)*P(A|B)P(A ∩ B) = (20/50) (19/49)P(A ∩ B) = 380/2450P(A ∩ B) = 38/245 or 15.51%
The probability that there will be two blue marbles among the five drawn marbles is 38/245 or 15.51%
We got the 15.51% by dividing 38 by 245. The quotient will be 0.1551. We then multiplied it by 100% resulting to 15.51%
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There are 57 variations that are above and then times that by 9 because the various will never repeat the same number like when you move onto 2's you'd replace all the 2 with 1's and so on and so forth
The answer is 513 variations
Answer:
112 candies
Step-by-step explanation:
Start from the end.
Joe gave 25% of the remaining candies to his sister and has 21 candies left. Then
Write a proportion:
Joe gave 7 candies to his sister, so before this he had 21 + 7 = 28 candies.
He gave 4/6 of what he had left to his brother when he went home, so 2/6 of all his candies left ot him. Hence,
Write a proportion:
Joe gave 56 candies to his brother, so Joe had 28 + 56 = 84 candies when he went home.
Joe gave 1/4 of his total candies to his classmates, so 3/4 of his candies left to him. So,
Write a proportion:
Therefore, initially, Joe had 28 + 84 = 112 candies.