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slega [8]
2 years ago
9

A clock that loses 5 seconds each hour has not been reset for 48 hours. What time does the clock show if the correct time is 8:4

9?
Pls solve asap! Brainliest!
Mathematics
2 answers:
AlexFokin [52]2 years ago
7 0

Answer:

it’s actually gonna be 12:49. the clock is losing seconds meaning that it’s behind the actual time.

Step-by-step explanation:

48x5 = 240 seconds

240/60 = 4 hours

8:49 + 4 hours = 12:49

kow [346]2 years ago
4 0
12:49 because the clock is loosing time so it would be behind time
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G(x)=−3x−8<br><br> g( )=10<br><br> what's in the parenthesis
Kazeer [188]

Answer:

2

Step-by-step explanation:

G(x)=-3x-8
  x + 3x= -8

        4x=8

          x=\frac{8}{4}

          x=2
G(2)=10
o busca mejor en internet

5 0
2 years ago
An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th
anastassius [24]

Answer:

0.288

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 17.48, \sigma = 3.25, n = 10, s = \frac{3.25}{\sqrt{10}} = 1.027740

Find the probability that the mean printing speed of the sample is greater than 18.06 ppm.

This is 1 subtracted by the pvalue of Z when X = 18.06. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18.06 - 17.48}{1.027740}

Z = 0.56

Z = 0.56 has a pvalue of 0.712

1 - 0.712 = 0.288

The answer is 0.288

7 0
3 years ago
HELP PLEASE!!!!!!!!!
Luba_88 [7]

Answer:

z

Step-by-step explanatio you got this bro

7 0
4 years ago
What is the point slope equation of the line with slope -12 that goes through the point (5,3)
atroni [7]
Point-slope
y - y1 = m(x - x1)
y - 3 = -12(x - 5)
6 0
4 years ago
The perimeter of the rectangle is 34 cm. The perimeter of the triangle is 30 cm. Find the value of n. a. 10 cm c. 14 cm b. 12 cm
swat32
I believe the value of N is B. 12 CM

6 0
3 years ago
Read 2 more answers
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