Answer:
Step-by-step explanation:
Given: MN ≅ MA
ME ≅ MR
Prove: ∠E ≅ ∠R
From the given diagram,
YN ≅ YA
EY ≅ RY
<EMA = <RMN (right angle property)
EA = EY + YA (addition property of a line)
NR = YN + RY (addition property of a line)
EA ≅ NR (congruent property)
ΔEMA ≅ ΔRMN (Side-Side-Side, SSS, congruence property)
<MNR ≅ MAE (angle property of congruent triangles)
Therefore,
<E ≅ <R (angle property of congruent triangles)
The range is a set of elements from the second set.
Therefore your answer is:
<h3>D. { -4, 1, 7, 15 }</h3>
Hi there!
(3/2)2+4<span>÷2*3 = 9
Hope this helps! :)</span>
Answer:
Circumference(C) of the circle is given by:
![C = 2 \pi r](https://tex.z-dn.net/?f=C%20%3D%202%20%5Cpi%20r)
where, r is the radius of the circle.
As per the statement:
A circular swimming pool has a radius of 15 ft.
⇒radius of the pool(r) = 15 ft
There is a path all around that pool that is three feet wide.
⇒radius of the outer edge of the path around the pool(r') = 15 +3 = 18 ft
Substitute these in the formula we have;
![C = 2 \pi r'](https://tex.z-dn.net/?f=C%20%3D%202%20%5Cpi%20r%27)
⇒![C = 2 \cdot 3.14 \cdot 18 = 113.04 ft](https://tex.z-dn.net/?f=C%20%3D%202%20%5Ccdot%203.14%20%5Ccdot%2018%20%3D%20113.04%20ft)
Therefore, the circumference of the outer edge of the path around the pool is, 113.04 ft