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belka [17]
3 years ago
8

If

Aand%5C%3A%20s-r%20%3D4" id="TexFormula1" title="log_8 N = \frac{r}{2} \: , \: log_2(2N)= 5\:and\: s-r =4" alt="log_8 N = \frac{r}{2} \: , \: log_2(2N)= 5\:and\: s-r =4" align="absmiddle" class="latex-formula"> Find N
Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0

Answer:

  N = 16

Step-by-step explanation:

The only relevant given piece of information is ...

  log2(2N) = 5

  2N = 2^5 = 32 . . . . . take antilogs

  N = 16 . . . . . . . . . divide by 2

_____

<em>Additional comment</em>

From log8(N) = r/2, you have log8(N^2) = r, or ...

  r = log((2^4)^2)/log(2^3) = 8/3

and ...

  s = 4 +r = 20/3

Rudik [331]3 years ago
4 0

Answer:

N = 2\frac{3r}{2}

Step-by-step explanation:

You might be interested in
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
2/3(6c+4)-(8c-5) Please explain how to do the problem.
irga5000 [103]
2/3(6c+4)-(8c-5)
1) Get rid of the negative signs
New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
2) Use distributive property for the first part by multiplying 2/3*6c= 4c and 2/3*4= 2 2/3
New equation: 4c+2 2/3+ (-8c) + 5
3) Combine like terms: 4c+(-8c)= -4c and 2 2/3+5= 7 2/3
New and simplified equation: -4c+ 7 2/3
5 0
3 years ago
Can you fill the blank space; 19=8, 6=3, 70=7, 8=5, 4=4, 60=5, 15=7, 16=? 17=?<br><br>​
Inga [223]

Answer:

7

9

Step-by-step explanation:

key is the number of letters in each word

  • 16= sixteen= 7 letters
  • 17= seventeen= 9 letters

3 0
3 years ago
25 points!!!!!!!!
podryga [215]

Answer:

A is your answer, my guy

Step-by-step explanation:

4x1=4

3x-1=-3

5x1=5

4+(-3)+5=6

6x1=6

8x-1=-8

6x1=6

6+(-8)+6=4

4x1=4

2x-1=-2

6x1=6

4+(-2)+6=8

8 0
3 years ago
Simplify the expression 2√ 20 − 3√ 7 − 2√ 5 + 4√ 63 .
earnstyle [38]

Answer:

The simplified form is,

\boxed{\boxed{6\sqrt{5}+9\sqrt{7}}}

Step-by-step explanation:

The given expression is,

=2\sqrt{20}-3\sqrt{7}+2\sqrt{5}+4\sqrt{63}

=2\sqrt{4\times 5}-3\sqrt{7}+2\sqrt{5}+4\sqrt{9\times 7}

=2(\sqrt{4}\times \sqrt{5})-3\sqrt{7}+2\sqrt{5}+4(\sqrt{9}\times \sqrt{7})

=2(2\times \sqrt{5})-3\sqrt{7}+2\sqrt{5}+4(3\times \sqrt{7})

=4\sqrt{5}-3\sqrt{7}+2\sqrt{5}+12\sqrt{7}

=4\sqrt{5}+2\sqrt{5}+12\sqrt{7}-3\sqrt{7}

=6\sqrt{5}+9\sqrt{7}

8 0
4 years ago
Read 2 more answers
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