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zepelin [54]
2 years ago
9

How to solve -3y=-5x-12

Mathematics
1 answer:
Talja [164]2 years ago
3 0

To solve -3y=-5x-12 you would

have to divide everything in the equation by -3

Y=5/3x+4

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Perform the operation (9x^2+6x-7)+(-9x-5)
asambeis [7]

Answer:

9x^{2}-3x-12

9x^{2}+6x-7-9x-5

(Group liked terms)

9x^{2}+6x-9x-7-5

( subtract the numbers ) -7-5= -12

9x^{2}+6x-9x-12

( add similar elements ) 6x-9x=-3x

9x^{2}-3x-12

Step-by-step explanation:

8 0
1 year ago
Complete the table below.<br> HeLPP ILL GIVE BRAINLIEST!
makkiz [27]
Here...see the attachment

6 0
2 years ago
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How do I solve this?
Sonbull [250]

The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.

sec(<em>x</em>) = csc(<em>x</em>)

By definition of secant and cosecant,

1/cos(<em>x</em>) = 1/sin(<em>x</em>)

Multiply both sides by sin(<em>x</em>) :

sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)

As long as sin(<em>x</em>) ≠ 0, this reduces to

sin(<em>x</em>)/cos(<em>x</em>) = 1

By definition of tangent,

tan(<em>x</em>) = 1

Solve for <em>x</em> :

<em>x</em> = arctan(1) + <em>nπ</em>

<em>x</em> = <em>π</em>/4 + <em>nπ</em>

(where <em>n</em> is any integer)

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of

<em>x</em> = <em>π</em>/4   <u>or</u>   <em>x</em> = 5<em>π</em>/4

5 0
2 years ago
1) What is the first x in x + 3x = 16?
Lyrx [107]
1. x=22/5
2. x=4
3. x=4
5 0
2 years ago
Complete the solution of the equation find the value of y when x equals negative 30. -2x-3y=42
Rama09 [41]
-2 (-30) - 3y = 42
60 - 3y = 42
-3y = -18
y = 6
7 0
3 years ago
Read 2 more answers
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