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RSB [31]
2 years ago
12

A student said that the slope of the line through (8,4) and (2,2) is 3. What error could this student have made?

Mathematics
1 answer:
Sindrei [870]2 years ago
3 0

Answer:

I think it was B I did this yesterday

Step-by-step explanation:

You might be interested in
Please tell me the answer
ddd [48]

Answer:

4x+6y³

Step-by-step explanation:

2x+x+x+2y×3y×y

=3x+x+2y×3y²

=4x+6y³

i hope it will help you

7 0
3 years ago
Read 2 more answers
What is 118/13 = 59/z?
gulaghasi [49]
If you're finding the value of z, z would equal 13/2 or 6.5
:)
7 0
3 years ago
Read 2 more answers
To rent a certain meeting room a college charges a reservation fee of $33 and an additional fee of $9.80 per hour the club wants
sammy [17]

Answer:

They must rent for less than 7 hours

Step-by-step explanation:

The charge for the room is the fee plus the hourly rate times the hour

f = 33+9.80t

This must be less than 101.60

101.60> 33+9.80t

Subtract 33 from each side

101.60-33> 33-33+9.80t

68.6> 9.80t

Divide each side by 9.8

68.8/9.8 > t

7>t

They must rent for less than 7 hours

7 0
2 years ago
Find the p​-value in a test of the claim that the mean College Algebra final exam score of engineering majors equal to​ 88, give
Orlov [11]

Answer: 0.9332.

Step-by-step explanation:

Claim : College Algebra final exam score of engineering majors equal to​ 88.

Given that : The  test statistic is z equals to 1.50.

To find the  p​-value (Probability value), we use standard normal distribution table, and search the p-value corresponds to the z-score.

In a Standard Normal Distribution Table below, the p-value corresponds z equals 1.5 is 0.9332.

Hence, the p​-value is  0.9332.

8 0
3 years ago
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\
\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}
100x&=&09.0909\overline{09}\\
&&9+0.0909\overline{09}\\
&&9+x
\end{array}\quad \implies 100x=9+x\implies 99x=9
\\\\\\
x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\
-------------------------------\\\\
\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}
\\\\\\
\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
3 years ago
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