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Scorpion4ik [409]
2 years ago
6

Plz help me with this assignment! I need help asap!

Mathematics
2 answers:
BigorU [14]2 years ago
7 0

Answer:

(a) 1.21 (b) 0.52

Step-by-step explanation:

Sophie [7]2 years ago
3 0

Answer:

3). 1.21

4). 0.57

Step-by-step explanation:

Quarter = 25 cents

Nickel = 5 cents

Penny = 1 cent

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The mass of a penny was measured six times. The following data was reported:
Scrat [10]

Answer:

a) 8.103 g

b) 9.2948

c) 0

Step-by-step explanation:

Given:

Data reported:

9.314 g, 9.215 g, 9.323 g, 8.103 g, 9.278 g, and 9.344 g

Now,

All the values except the 8.103 are above 9

Here the data 8.103 varies very much with respect to the other values

Hence,

a) the data 8.103 should be excluded

b) average value of the mass of the penny = \frac{9.314 + 9.215 + 9.323 + 9.278 + 9.344 }{5}

= 9.2948 g

c) Deviation = Mean - Data

9.2948 - 9.314 = -0.0192

9.2948 - 9.215 = 0.0798

9.2948 - 9.323 = -0.0282

9.2948 - 9.278 = 0.0168

9.2948 - 9.344 = -0.0492

Thus,

Average deviation from mean = tex]\frac{-0.0192 + 0.0798 -0.0282 + 0.0168 -0.0492 }{5}[/tex]

= 0

4 0
3 years ago
Evaluate the expression:<br><br> 2/3-1/4+(-5/6)
Aliun [14]

Answer:

\\  \frac{2}{3}  -  \frac{1}{4}  +  \frac{( - 5)}{6}

\\  =  \frac{2}{3}  -  \frac{1}{4}  -  \frac{5}{6}

\\  =  \frac{8 - 3 - 10}{12}

\\  =  \frac{8 - 13}{12}

\\  =  \frac{ - 5}{12}

3 0
2 years ago
D. Write a system of two linear equations that has more than one solution.
ddd [48]
D. y=5x+6 and 2y-12-10x=0 has infinitely many solutions and both lines are linear

E. y=4x+1, y=9x+4 has the solutions x = -3/5, y = -7/5


3 0
3 years ago
OMG PLEASE Help me !!!! ILL GIVE YOU BRAINLIEST !!! Explain in order to get it
Doss [256]

Answer:

I'm not sure but I believe the correct answer is line L2.

Step-by-step explanation:

It seems to be closer to more points than the other lines.

If it is not L2, it must be L3.

4 0
3 years ago
Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]

X' = U - X

= {1,2,3,4,5,6} - {1,4,5}

= {2,3,6}

(ZUX') = {2,3,5} U {2,3,6}

= {2,3,5,6}

(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}

= {2}

3 0
3 years ago
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