Answer:
a) 8.103 g
b) 9.2948
c) 0
Step-by-step explanation:
Given:
Data reported:
9.314 g, 9.215 g, 9.323 g, 8.103 g, 9.278 g, and 9.344 g
Now,
All the values except the 8.103 are above 9
Here the data 8.103 varies very much with respect to the other values
Hence,
a) the data 8.103 should be excluded
b) average value of the mass of the penny = 
= 9.2948 g
c) Deviation = Mean - Data
9.2948 - 9.314 = -0.0192
9.2948 - 9.215 = 0.0798
9.2948 - 9.323 = -0.0282
9.2948 - 9.278 = 0.0168
9.2948 - 9.344 = -0.0492
Thus,
Average deviation from mean = tex]\frac{-0.0192 + 0.0798 -0.0282 + 0.0168 -0.0492 }{5}[/tex]
= 0
D. y=5x+6 and 2y-12-10x=0 has infinitely many solutions and both lines are linear
E. y=4x+1, y=9x+4 has the solutions x = -3/5, y = -7/5
Answer:
I'm not sure but I believe the correct answer is line L2.
Step-by-step explanation:
It seems to be closer to more points than the other lines.
If it is not L2, it must be L3.
Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]
X' = U - X
= {1,2,3,4,5,6} - {1,4,5}
= {2,3,6}
(ZUX') = {2,3,5} U {2,3,6}
= {2,3,5,6}
(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}
= {2}