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bearhunter [10]
2 years ago
15

2. When there is a strong positive, how do the points look?

Mathematics
1 answer:
motikmotik2 years ago
5 0

When there's a strong positive, the points are: B. Close together.

<h3>Strong Positive Relationship</h3>
  • On a scatter plot, if the data points are close together along the trend line sloping upwards, it means there's a strong positive correlation.
  • Strong positive correlation means the two variables change in the same direction.

Therefore, when there's a strong positive, the points are: B. Close together.

Learn more about strong positive relationship on:

brainly.com/question/15552860

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If Lin runs 21 laps at the same rate (1.2 minutes per lap) how long does it take her?
Firlakuza [10]

Answer:

It takes her 25.2 mintes

Step-by-step explanation:

You can just multiply 21 by 1.2 because that's how long she takes per lap and you can get 25.2

8 0
2 years ago
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If the dimensions of the following cylinder are doubled, what factor will the surface area change by?
Vedmedyk [2.9K]

Answer:

probably 2 or 4

Step-by-step explanation:

7 0
3 years ago
Is y = |x + 3| a linear function yes or noO
vekshin1

Answer:

Yes

Step-by-step explanation:

Because it passes vertical line test.

4 0
3 years ago
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34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ?
Dominik [7]

Answer:

HJ=20\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

RT and GJ are chords that intersect at point H. If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ? 18 units 20 units 26 units 28 units

we know that

The <u><em>intersecting chords theorem</em></u>  is a statement that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal

so

In this problem

(RH)(HT)=(GH)(HJ)

substitute the given values

(10)(16)=(8)(HJ)

solve for HJ

HJ=160/8\\HJ=20\ units

7 0
3 years ago
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