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2 years ago

Examples:

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

5 0

Answer:

1. 9 + 4

2. 46 + 10

3. 18 + 14

4. 10x+ 14

5. 17 + 32

6. 5 + 7- 5

7. 3 + 70

8. 3 + 20 + 10

9. 7 + 16

10. 7 + 5

11. 9 + 120

12. 12

13. 6 + 15 +

14. 2 - 19+ 12

15. 3 + 14 - 31

Step-by-step explanation:

You might be interested in

A study conducted to determine the relationship between the age, x, in years of a certain brand of motorcycle and its value, y,

kirza4 [7]

Based on the equation, y = -750·x + 8500, the estimated value of a

motorcycle that is 5 years old is $4,750.

<h3>How can the given equation help to estimate the value of the motorcycle?</h3>

The regression equation that models the data is; y = -750·x + 8500

Where;

y = The value of the brand of motorcycle in dollars

x = The age of the motorcycle

When the motorcycle is 5 years old, we have;

x = 5

y = -750 × 5 + 8500 = 4750

Based on the equation, the estimated value of a motorcycle that is 5 years old, y = $4,750

Learn more equations here:

brainly.com/question/20475360

4 0

3 years ago

HELP PLEASE HELP ME FIND THE AREA!!

nikklg [1K]

Answer:63.75 ez

Step-by-step explanation:

first you multiply 10 x 8.5 and then divide by 2=85, after that you you divide by 2 =42.5 and you see the little triangle thats 42.5/2 wich is equal to 21.25 so after all of that you add 42.5+21.25 and you get the answer

6 0

3 years ago

Read 2 more answers

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$